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Hi all, i have a typical wired doorbell setup, the transformer is a m412 RDL next to the consumer unit. My biggest concern is the output from this the transformer is not fused, it just wires directly into the chime as you would expect, then from the chime a cable to the bell push. I know its extremely unlikely that the bell wire would ever become damaged or short circuit, but if it did i worry it would just melt as there is no fuses visible on the transformer output, unless its internal in the transformer like a thermal type?
I know the output is around 8 to 12v, but in the event of a short circuit I somehow doubt the ouput would have sufficient current to trip the b6 circuit breaker on the mains side and i fear the bell wire would just melt.
Is it common/ likely that bell wire is unfused? Or will the transformer have some form of protection for the output built internally like a polyswitch or something similar?
Thanks.
I will see if i can get pictures of the set up later on.
I know the output is around 8 to 12v, but in the event of a short circuit I somehow doubt the ouput would have sufficient current to trip the b6 circuit breaker on the mains side and i fear the bell wire would just melt.
Is it common/ likely that bell wire is unfused? Or will the transformer have some form of protection for the output built internally like a polyswitch or something similar?
Thanks.
I will see if i can get pictures of the set up later on.