Calculator guesses your age

[tim west]

Quite neat little trick:

Pick any number between 1 and 100,000 (maybe the last four or five digits of your phone number).

Multiply it by 2.

Add 5.

Multiply the answer by 50.

If you have already had your birthday this year add 1758, if not add 1757*.

Subtract the four digit year that you were born.

You should see now your original number followed by your age.

*1758 and 1757 work for the year 2008. Add 1 for each year after this, for example in 2009 use 1759 and 1758.

 

[Bilioustrumpstaine]

Not really that clever mate.

Forget the first four numbers and take the number 5 x 50 = 250 add 1757 = 2007 take away your birth year will come to your age (suprise suprise)

 

[dave.m]

If you want a number puzzle try this one:

http://digicc.com/fido/

 

[Clitheroe]

I had always simply been told to take away your birth year from the current year (although this does not actually take into account if you have had your birthday yet in the current year)

 

[Shytalkz]

 

[tim west]

I had always simply been told to take away your birth year from the current year (although this does not actually take into account if you have had your birthday yet in the current year)

Blimey thats a good one???

 

[tim west]

Two chess masters played fifteen consecutive games of chess. No games were drawn, every game was finished, yet both players won and lost the same number of games as each other. How could this happen?

A brick weighs 1kg plus half a brick. How much does it weigh?


Six friends visited their local club to play at a pool tournament. The competition entry fee was £10 per person. Prize money was £250 for the winner, £100 for the runner-up, and £50 for third-place. There were no other prizes. None of the friends won a single game. There were no disqualifications, and yet the friends came away collectively £150 in profit from having played. How?

 

[solo]

 

[Trazor]

Two chess masters played fifteen consecutive games of chess. No games were drawn, every game was finished, yet both players won and lost the same number of games as each other. How could this happen?

They did not play each other.

A brick weighs 1kg plus half a brick. How much does it weigh?

2 Kg

Six friends visited their local club to play at a pool tournament. The competition entry fee was £10 per person. Prize money was £250 for the winner, £100 for the runner-up, and £50 for third-place. There were no other prizes. None of the friends won a single game. There were no disqualifications, and yet the friends came away collectively £150 in profit from having played. How?

Hmmmmmm....

 

[Spark123]

Two chess masters played fifteen consecutive games of chess. No games were drawn, every game was finished, yet both players won and lost the same number of games as each other. How could this happen?

Another game was played inconsecutively?
Prefer Trazor's answer to this one

A brick weighs 1kg plus half a brick. How much does it weigh?

2kg?

Six friends visited their local club to play at a pool tournament. The competition entry fee was £10 per person. Prize money was £250 for the winner, £100 for the runner-up, and £50 for third-place. There were no other prizes. None of the friends won a single game. There were no disqualifications, and yet the friends came away collectively £150 in profit from having played. How?

There was only one other player, who got the £250 and paid their entry fees?

 

[tim west]

The first two correct by trazor

last one wrong im afraid Spark

Can i get something for your headache solo?

 

[Spark123]

They won more than a single game each? Got the £250 and spent £40 on drinks?

 

[WDIK]

were they by any chance playing doubles?

lost the first match and no one else turned up

 

[tim west]

Nope and nope and nope

 

[Trazor]

They cannot make £150 profit, out of any permutation of the prize money, so, after losing £60 at pool, they won £210 on the bingo.............

This had better be good tim..............