Insulation R values

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Would somebody be so kind as to confirm something for me .
I am looking to board out my loft and in this process looking at insulation.
I have vermiculite up to the top of the joists which are approx 3" deep.
Know heres the query apparently you need an R value of between 6.1 and 7 at least in the loft , when i looked up the R value of vamiculite it is approx 2.4 per inch so 3 inches =7.2 plus you have a small amount with the boarding , so is it as easy as that ? cheers Mark
 
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It is recommend that lofts should be insulated to an R value of between 6.1 and 7 Km2/W.
I understand that vermiculite has a R value of 2.08 PI
So your R value for a full fill would be 6.24.
 
Thanks prenticeboy , it makes you wonder why all these people fret about
layers upon layers and then get there boarding down when it is a lot easier with these granules .
 
I personally don't like the granules, as they can get all over the place.
Prefer rook wool, but I don't expect us to like or prefer the same things.
If they do the job and float your boat that's great in my book!
 
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I suspect the previous Government were desperate to meet CO2 emission targets and thought that it would be good for everyone to upgrade their loft insulation. I am not convinced it is in householders' best interest as I suspect it might increase condensation/rot in loft timber.

The current recommendation is at least 250mm of mineral wool (K-value of 0.04). From http://www.dupreminerals.com/en/applications/insulation/loft Vermiculite has a K-value of 0.063 => 250 * 0.063/0.040 or roughly 400mm to get equivalent insulation. I'm afraid your 75mm looks pretty puny; equivalent to 50mm mineral wool.

Personally, I'd be happy with 150mm of mineral wool in a traditional built house. Last year I bought 170mm glass wool from Homebase for 50p/m². At that price, it would be worth adding to your loft.
 
ajrobb , i am confused are the R values meaningless then in respect of
the recommended level 6.1 to 7.0 which the 75mm of vamiculite equates to .
What i dont understand is the K values versus the R values perhaps you could enlighten me as i am not that spamed up on insulation cheers
Mark
 
R-values come in different units. On Canadian websites, where they acknowledge that imperial and metric measurements are both used, I have seen them listed as R for imperial and RSI for metric. American websites tend only to use imperial values. Some other values seem to be a mixture of metric and imperial!

The UK regulations use U-values, which is fine for working out heat loss but doesn't really acknowledge that R-values are more useful for working with insulation to conform to the regulations. R-values of individual layers are summed to get the overall R-value, which is the reciprocal of the overall U-value. There is no point working out U-values for individual layers but you can average the U-value for a wall with windows.

The K-value of a material does not depend on thickness. Rule-of-thumb K-values (SI units) include 0.115 for timber, 0.063 for Vermiculite, 0.040 for mineral wool and 0.024 for PIR. To calculate R-value, you divide the thickness (metres) by the K-value. Thus 250mm of mineral wool would have an R-value of 0.250 / 0.040 or 6.25, with a U-value of 1/6.25 or 0.16 W/m²/K. Now, this just shows that the term 'K-value' probably comes from the US or pre-dates SI. In countries using SI, the technical temperature unit is Kelvin (K), not to be confused with K-value for conductivity! It may be less confusing to use °C rather than K (same difference) and I could have used 0.16 W/m²/°C.

Things get more complicated by layers of more than one material (e.g. insulation between joists), you need the average K-value for the layer.

Take a typical 10% timber and 90% Vermiculite area ratio:
Average K-value for the layer is 0.115 x 10% + 0.063 x 90% = 0.068. Average R-value for 75mm joists with full-depth Vermiculite is 0.075/0.068 = 1.10. However, it doesn't stop there! I haven't included R-values for 12.7mm plasterboard (0.08 ), the warm (0.13) and cold (0.04) surfaces. The overall R-value for the ceiling would be 0.13 + 0.08 + 1.10 + 0.04 = 1.35. Now I am in a position to calculate the U-value for the ceiling as 1/1.35 = 0.741 W/m²/K.

If you use space blanket instead of bare mineral wool, say, the low-emissivity (reflective) top surface will add another 0.40 R-value for a vented reflective cavity to the overall equation. However, as the top reflective surface gets dirty, this benefit is lost.

From wikipedia:

"The conversion between SI and US units of R-value is 1 h·ft²·°F/Btu = 0.176110 K·m²/W, or 1 K·m²/W = 5.678263 h·ft²·°F/Btu"
 
Thanks ajrobb for taking the time to put that together , i think i am more
enlightened if not i will read it till i am , cheers mark
 

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