I gather 'the old system' (pre-part L) recommended 4 air changes per hour generally in domestic premises but that was for an average air-tight building. Given the one in question is a bit more airtight, let's go with three. What follows is a calculation to determine what three changes of air per hour will cost in terms of energy:
House is 130m2 floor area x 2.5m (ceiling height) = 325m3
Density of air is 1.2 kg/m3
Weight of air lost each hour is therefore: 3 air changes x 325m3 x 1.2kg/m3 = 1170kg (sounds insane!)
Specific heat capacity of air = 1000J/kg/degC.
1J = 0.000000277777778kWh
If we use an ambient outdoor temperature of 0degC and raise it to 20degC (Δθ = 20), the amount of energy (ΔQ) needed per hour to do this is:
ΔQ = mcΔθ
ΔQ = 1170kg x 1000J/kg/degC x 20degC = 23,400,000J x 0.000000277777778kWh = 6.5kWh ... and that's every hour.
Is it just me or isn't this patently ridiculous as the cost would be astronomical... (or my maths could be adrift!)
MW
House is 130m2 floor area x 2.5m (ceiling height) = 325m3
Density of air is 1.2 kg/m3
Weight of air lost each hour is therefore: 3 air changes x 325m3 x 1.2kg/m3 = 1170kg (sounds insane!)
Specific heat capacity of air = 1000J/kg/degC.
1J = 0.000000277777778kWh
If we use an ambient outdoor temperature of 0degC and raise it to 20degC (Δθ = 20), the amount of energy (ΔQ) needed per hour to do this is:
ΔQ = mcΔθ
ΔQ = 1170kg x 1000J/kg/degC x 20degC = 23,400,000J x 0.000000277777778kWh = 6.5kWh ... and that's every hour.
Is it just me or isn't this patently ridiculous as the cost would be astronomical... (or my maths could be adrift!)
MW