No, not unless we start talking about ridiculously high voltages, high enough to still cause enough current to flow through the coil despite the low-resistance shunt across it.
Ohms law will dictate that the current required to trip the mechanism will being flowing if the potential difference between the E and F terminals is 50 volts or more. There is no need to have "ridiculously high voltages" across the coil. The current through the fault will also be determined by ohms law with 50 volts applied to the resistance ( impedance ) of the fault circuit.
The fault current will raise the potential of the ground in the "resistance area" and thus reduce the voltage difference between E and F thus reducing the current in the coil. The raising of the potential of the "resistance area" compared to ground outside the "resistance area" means the CPC could be considerable more than 50 volts above any ground that is outside the "resistance area".Yes, if there is anything else (connected directly to the "F" terminal) placed within the resistance area of that electrode,
In short any parallel path that connects to ground inside the "resistance area" will result in the CPC reaching voltages higher than 50 volts before the trip operates.