Conveyor's conveyor.

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Blas, could you explain how, using a longwinded and extremely boring description of the physics behind it and what the bloke down the pub reckons, cheers :D
 
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Blas, could you explain how, using a longwinded and extremely boring description of the physics behind it and what the bloke down the pub reckons, cheers :D

As my previous post on this subject will affirm, my answers are always long winded and extremely boring Mr West..... :D

The wheels of an aircraft DO NOT provide propulsion or forward motion to the aircraft and therefore do not 'push against' the action of the conveyor belt. Any forward motion (thrust), comes from the engines or propellers not the wheels. Forward motion/Thrust therefore is being applied to the aircraft 'body'. It has NOTHING to do with how fast or slow the wheels happen to be 'spinning/free-wheeling'.

According to Newtons Third Law of Motion, every action has an equal and opposite reaction. The thrust of the engines is acting against the 'air'. Because the wheels are free-wheeling the conveyor belt cannot exert any force on the aircraft with respect to forward motion. All that it will do is make the wheels spin faster or slower. There is no force in this scenario that is opposing the thrust vector of the aircraft. Therefore if the conveyor belt cannot exert any force on the aircraft, which it cannot because as we now know, the wheels spin/free-wheel, the aircraft will take off.

I assume we still have the conveyor belt.....?

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Blas - you were and are completely correct. There are no action/reaction forces involved in the rotation of the wheels and the point of contact between the tyre and conveyor belt, and therefore the plane will move until the appropriate relative vacuum between the lower and upper surfaces of the wings is sufficient to create enough lift.

If this were not the case, then planes would take an inordinate distance to take off from low friction surfaces such as ice and water.
 
The wheels of an aircraft DO NOT provide propulsion or forward motion to the aircraft and therefore do not 'push against' the action of the conveyor belt. Any forward motion (thrust), comes from the engines or propellers not the wheels. Forward motion/Thrust therefore is being applied to the aircraft 'body'. It has NOTHING to do with how fast or slow the wheels happen to be 'spinning/free-wheeling'.

According to Newtons Third Law of Motion, every action has an equal and opposite reaction. The thrust of the engines is acting against the 'air'. Because the wheels are free-wheeling the conveyor belt cannot exert any force on the aircraft with respect to forward motion. All that it will do is make the wheels spin faster or slower. There is no force in this scenario that is opposing the thrust vector of the aircraft. Therefore if the conveyor belt cannot exert any force on the aircraft, which it cannot because as we now know, the wheels spin/free-wheel, the aircraft will take off.

I'm not sure I follow. Can you expand? ;)
 
Wouldn't their be friction at the axle? (Conveyor belt, more axles, more friction, less efficiency)
 
I wasn't referring to the plane on the conveyor belt but the picture in the 1st post. (I didn't know there was another post :oops: )
 
So if the wheels spin when the plane is stationary then how can it take off?
:D
 
I don't see that the tracks are propelled in any way other than the aircraft moving from its propulsion reactive forces. If the track was self propelled why would you need a towing arm like that fitted to the front oleo in picture 3?
 
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