if a 24kW boiler is connected rads which add up to a nominal 30kW, they will give out 24kw (as that's the most the boiler can supply). But the flow and return temperatures will be 67C and 57C, even if the boiler stat is set to 80C. It's called thermal equilibrium.
Would you like to explain that?
The output of a boiler is determined by the flow rate and the temperature differential: kW = litres/
sec x ΔT X 4.18. Note that the actual temperatures are not relevant, so a boiler running at 80/70 will have the same output as one running at 60/50
provided the flow rate is the same. (I'm ignoring the increased output due to condensing). The flow rate for a 24kw boiler with a 10C differential is 34.45 litres/
min.
If you connect a 24kW boiler to 24kW of rads and let it run without any temperature control it will heat up until the rad output exactly matches the boiler input.
The output of a radiator is determined by room, flow and return temperatures, which are:room temp = 20C; flow = 75C; return = 65C (i.e 10C differential).
Now connect 30kW of rads to the same 24kW boiler. The flow rate is the same as the pump has not been changed, so the boiler cannot produce more than 24kW. The question then is: at what temperature will the 30kW of rads produce 24kW of heat when the flow rate is 34.45 litres/min?
The answer can be found by referring to the temperature table, which can be found in any rad manufacturer's catalogue. This give the correction factor which must be applied when the temperature difference between rad mean temp and room temp is not 50C [((75+65)/2) -20].
The required correct factor for 30kW rads and a 24kW boiler is 24/30 = 0.8. The Stelrad table only shows factors in 5C steps: 40C = 0.748; 45C = 0.872. If we assume a linear relationship, 0.8 = 42C. So the mean rad temp is 20+42 = 62C, or 67C flow and 57C return.