There is no maximum see
here but they have go to tell you what it is.
Statutory Instrument 2002 No. 2665
The Electricity Safety, Quality and Continuity Regulations 2002 states:-
Information to be provided on request
28. A distributor shall provide, in respect of any existing or proposed consumer's installation which is connected or is to be connected to his network, to any person who can show a reasonable cause for requiring the information, a written statement of -
(a) the maximum prospective short circuit current at the supply terminals;
(b) for low voltage connections, the maximum earth loop impedance of the earth fault path outside the installation;
(c) the type and rating of the distributor's protective device or devices nearest to the supply terminals;
(d) the type of earthing system applicable to the connection; and
(e) the information specified in regulation 27(1),
which apply, or will apply, to that installation.
Single of 3 phase supply up to 100 amps - Cable sheath earth terminal 0.8 ohms
Single phase supply up to 100 amps - PME or PNB earth 0.35 ohms
Is the normal figures given to designers of new builds before a supply is given. To be honest many heads have no real way to work out if TN-S or TN-C-S since the combining and splitting of neutral and earth does not necessary need to be done at the head. The Prospective fault current Ipt should be less than 16 kA ( 1 phase ) see
here which is not really helpful but to maintain a supply within the +10% and -6% limits for a 100A supply with TN-C-S the impedance will need to be 0.368 ohms and with a 60A supply 0.613 ohms so that no load does not exceed 266.8 volt or full load not below 216.2 volt simple maths. Now 0.368 ohms is very close to the 0.35 ohms normally considered as max for TN-C-S and I would not think any supplier would want to be running right on the limit so it would seem a reasonable figure to expect. I would expect the Ipt to exceed 625A (with 100A fuse) if the supply is to keep within volt drop limits what did you measure?