How do you arrive at 38% ?
Your previous 20% for 75/55/20 seems to have been too low.
The equation I used is the "Radiator Enlargement Ratio" as shown in
Formulas published by Danfoss Heating. The same formula is used for sizing radiators on a single pipe systems due to the drop in flow and return temperature as you proceed along the chain from the boiler.
If you look at the Temperature Table on page of the
Stelrad Elite Catalogue, you will see that the factors are not linear. (This table shows the change in rad output from norm) You would expect a rad running with a mean difference of 40C to produce 80% of the output of one running with a mean of 50C, but it doesn't. As the table shows, it only produces 74.8%. Similarly for a difference of 25C the output is 40.6%, not the expected 50%. This table assumes that the difference between flow and return temperatures stays constant at 10C.
If a boiler is used which runs best with a 20C differential, the factors are virtually the same, provided the mean rad temperature is the same, e.g 80/60 instead of 75/65.
In the example I gave with a boiler running at 70/50 the mean temperature is 60C and the difference is 40C (60-20, room temperature).
Using the table in the Elite catalogue the factor for a 40C difference is 0.748; i.e a nominal 1000W radiator will give out 748 watts. So if you need 1000 watts, you will have to install a rad which is nominally 1000/0.748 = 1,337 watts., an approx 34% oversize
However if you use the formula I gave the link to, you will find that the enlargement factor is actually 1.378, i.e an approx 38% oversize.
I haven't been able to account for the few percentage points difference.