Yes agreed but in this context i think the op is more likely to have an idea of circuit length than have the appropriate equipment to measure zs.
Yes, probably true but, as I said, actually determining the length of an existing ring really requires measurement of R1 or R2 and, even then, that can only be translated into a VD by the use of assumptions.
Also you can measure zs directly but in theory you should measure ze and then add on the R1+R2 just in case there's a boiler or similar nearby on the ring, which may later disappear.
Again, I suppose that's theoretically true, but I wonder how often it's actually done like that? Apart from anything else, other than as a means of measuring Ze (rather than assuming a value 'by enquiry'), it would mean that folk would not require a means of loop impedance measurement!
Put another way, do you think that people would actually 'fail' a circuit if Ze+R1+R2 was above the 'maximum permitted' even though a (current) Zs measurement was below the required maximum? Whilst it is true that "...there could be a boiler or similar nearby on the ring, which may later disappear.", so is it possible that the Ze might subsequently change - so I'm not sure to what extent one should (or needs to) take into account 'future possibilities', rather than just rely on 'current measurements'?
Furthermore, as above, estimating VD also theoretically requires measurement of R1 or R2 (to determine ring length), as well as the assumptions, so there's not that much difference.
In any event, we are agreed that determination of the maximum circuit length theoretically requires consideration of both Zs and VD. Whilst, numerically, VD may well be the length-limiting-factor (particularly with TN-C-S), I would personally feel that it is by far the 'less important' of the two. Apart from anything else, given that the majority of installations probably have a supply voltage around 10% above the 'minimium permitted', I would find it hard to get excited about a circuit which, if fully loaded (itself very unlikely), would have a VD a bit over 5%!
Kind Regards, John