I'm not sure I would necessarily say that, since most of what you go on to say is very logical.It gets more complicated.
Exactly. That's why/how the smaller capacitor is being used as a 'dropper'.Given that two capacitors in series ( with no other components ) will have the same amount of charge ( current x time ) then the smaller capacitor will have a higher voltage ( V = charge / capacity ) than the larger capacitor
Again, exactly. You're really just describing the function of the 10 uF 'smoothing capacitor.But with 1 Watt LED lamps with a full wave rectifier between the capacitors the circuit becomes a charge pump. The charge that passes through the 0.47 uF capacitor passes into the 10 uF capacitor. The rectifier bridge prevents that charge leaving the 10 uF when the AC reverses. Instead when the AC reverses the 10 uF capacitor gets another 0.47 uF worth of charge thus increasing the voltage on the 10 uF capacitor. Eventually the voltage on the 10 uF capacitor becomes high enough for the LED elements to light and also act as a pseudo Zener diode.
Do you therefore agree that, with the rectifier diode changed to a bridge, and with the resistor replaced by a ('fairly low value') capacitor, that the fan timer module would work satisfactorily?
I suppose that's not all that surprising given that, as you say, the LED elements are essentially acting like a zener, despite the fact then you then have two 0.47 uF capacitors in series in the current path. However, if you started reducing the value of those 0.47 uF capacitors (or, as I do for dimming, add a further capacitor in series with it all) I would expect that you would fairly soon reach the stage at which the LEDs did start getting dimmer.These LED lamps are rated at 230 V but two in series ( 115 V each ) appear be as bright as they are on 230 V.
Kind Regards, John
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