That was quick.
Edited previous post - 42.5A @ 250V but we have to use 230 so ok.
Edited previous post - 42.5A @ 250V but we have to use 230 so ok.
hey scouse
what do you think the current is at 230v then?
I was interested to know what you thought the current was at 230v, as you thought it was not suitable for a 40A MCBNo it isn't (for either voltage)
The original post quoted 9.8KW.
You used 240 and got 40.8A. Using 230 gives 42.6A.
9.8kW (@240v).
The original post quoted 9.8KW.
You used 240 and got 40.8A. Using 230 gives 42.6A.
the 9.8kW was at 240v. The 230v current is always lower.
9.8kW (@240v).
Not in a purely resistive load which will not change impedance depending on the voltage applied to it. The impedance / resistance will increase by a percent or two as its operating temperature rises but for calculation purposes it can be considered as constant for all applied voltages when calculating current through it.Reducing the voltage increases the current drawn.
Nor is it difficult to grasp that if a shower draws 40.83A at 240V it will not draw 43.61A at 230V.The original post quoted 9.8KW.
You used 240 and got 40.8A. Using 230 gives 42.6A.
the 9.8kW was at 240v. The 230v current is always lower.
9.8kW (@240v).
This is not a difficult maths problem.
9800 / 240 = 40.83A 9800 / 230 = 42.61A
No.Reducing the voltage increases the current drawn.
No.I am not referring to the manufacturer quoting 9KW at 230V.
How on earth is "Reducing the voltage increases the current drawn" keeping it simple for the OP?
And bas is trying to say that noone with a clue about electrics and dealing with a resistive load would do that.How on earth is "Reducing the voltage increases the current drawn" keeping it simple for the OP?
It doesn't and it's a poor choice of wording. I was only trying to show that taking 9.8 as the starting point, dividing by 230 is going to increase the figure.
S0 - now the hallowed MIs are for guidance only.The 230/240v kw and MCB ratings are for guidance only..
And bas is trying to say that noone with a clue about electrics and dealing with a resistive load would do that.How on earth is "Reducing the voltage increases the current drawn" keeping it simple for the OP?
It doesn't and it's a poor choice of wording. I was only trying to show that taking 9.8 as the starting point, dividing by 230 is going to increase the figure.
I'm not a fan of what bas's recent behvaiour and if I was a moderator he would have been warned multiple times and probablly banned by now but in this case he is right.
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