Two appliances in one plug

[bernardgreen]

Heck with all the new names.

Fe02 = Iron(II) Oxide then surely Fe2O3 = Iron ( III/II ) Oxide.

I need to calorate some di-hydrogen mon-oxide to make a cuppa.

 

[JohnW2]

Heck with all the new names.
Fe02 = Iron(II) Oxide then surely Fe2O3 = Iron ( III/II ) Oxide.

Initially, a big Whoops here. I started, and eveyone else failed to notice, incorrectly stating the formula of ferrous oxide (Iron II oxide) as FeO2, whereas it obviously should be FeO.

Having said that, the answer to your question is No .... The (II) and (III) refer to the valency (valence, oxidation state) of iron in the compound in question:

FeO (ferrous oxide, iron II oxide) O=Fe ... Fe valency = 2 (2 bonds)

Fe2O3 (ferric oxide, iron III oxide) O=Fe-O-Fe=O ... Fe valency = 3 (3 bonds)

Kind Regards, John.

 

[echoes]

Just for completeness' sake,

Fe3O4 is Iron (II,III) oxide.

Hope you enjoyed your cuppa bernard. Do you take C12H22O11?

 

[JohnW2]

Just for completeness' sake,
Fe3O4 is Iron (II,III) oxide.

Ah, yes, magnetite. Structurally, IIRC, that's a combination of FeO and Fe2O3.

...and you were in good company in not noticing my "FeO2" deliberate error

Kind regards, John.

 

[echoes]

...and you were in good company in not noticing my "FeO2" deliberate error icon_smile.gif

Err... umm.. just humouring you, obviously...