flameport said:
Interesting - but whilst they are describing something that could result in 'consistently incorrect' loop impedance measurements, I don't see how could it explain the varying measurements that the OP has observed. What am I missing?
However, there are aspects of that article which I find difficult to understand. They start by saying ....
Higher currents reduce coil impedance ....
... and they their diagram goes on to indicate:
0.5 Ω @ 15 mA
0 Ω at 100 mA
..... can you help me understand this 'dramatically current-sensitive impedance' ? The resistance of that coil, in the main path (and also the one in the neutral path) obviously mst be 'close to zero' for significant currents,otherwise it could cause a massive VD and get very hot when carrying high currents.
They then go on to say ...
Higher currents reduce coil impedance but will cause the RCD to trip, preventing the test from completing.The impedance of the coil (A) at 15 mA is 0.5 Ω. This value is added to the basic circuit impedance and the total is displayed on the MFT. The MFT cannot distinguish between the impedance of the circuit and that of the coil.
... which seems to imply that the MFT will always display a loop impedance which is 0.5 Ω (or whatever) too high when the circuit is not loaded. Is that what they are saying?
... and then the go on further to say ....
It is irrelevant how much current is flowing in the L-N circuit. The example in Figure 3 shows the test process in a more realistic circuit, with a motor load and a loop impedance test.
... it is true that the device should not then trip (2.015 A through L and 2.000 A through N, hence residual current of just 15 mA). However, since 2.015 A is a lot higher than 100 mA, they appear to be suggesting that the impedance of the coil would then be 'zero', in which case the meter presumably ought to give an accurate measurement of L-PE loop impedance if the load on the circuit is resulting in at least 100 mA of current flowing, shouldn't it ?
As you can see, there's a fair bit there that I don't really understand, so I wonder if you can help me at all?
Kind Regards, John