Not quite. Provided the Vfs are low enough in relation to the battery voltage, having two LEDs without a resistor is not conceptually different/worse than having one without a resistor - in both cases the issue is that the current is unpredictable.
In that case, one probably needs a crystal ball to predict what would happen with any particular LED.
Indeed, as I said.
Maybe. The question is what current would flow from a (new) 3V cell through it, and whether that would be within its maximum current-carrying capability. Your experiment will tell you.I've got LED's with a max. forward voltage of 3.6V which I am informed (by various sources) will work all day long with a 3V cell.
Do you mean series or parallel? If you put them in series across a 3V cell then, as has been said, whether or not they light at all is dependent on their characteristics, so for you to discover by experiment. If you put them in parallel across the 3V cell (with no resistors), they would each carry roughly half the current that would go through one across the 3V cell (without a resistor), since they would be 'sharing' the internal resistance of the cell.
So far, so good, then. Have you measured how much current is flowing?
It's difficult (at least for me!) to be sure what he's dealing with on the basis of the 'data sheet' in the eBay listing. The 3.6V is specified as the 'maximum Vf' (seemingly at 30mA), but it's not just an LED (must have some flasher electronics) - so that figure may just be the 'maximum supply voltage', rather than Vf of the LED.
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