Physics question 2...

[sooey]

Why haven't the pyramids at Giza disappeared

They were eleventeen thousand feet tall when they were first built.

 

[oompah]

 

[lifesagasman]

Why haven't the pyramids at Giza disappeared

They were eleventeen thousand feet tall when they were first built.

Yeah, the footings were a nightmare....bloody sand....

 

[geraint]

Why haven't the pyramids at Giza disappeared

They were eleventeen thousand feet tall when they were first built.

Yeah, the footings were a nightmare....bloody sand....

so get your bucket and spade out.....

 

[lifesagasman]

Isn't it past your bedtime?

 

[geraint]

why would you say that.

 

[lifesagasman]

I followed your posts during the (rare) thread that I started until your trolling caused it to get locked. I have no wish to engage further with your posts.
You're now back on ignore.

 

[geraint]

any object on a sphere that rotates once per day, no matter how big the sphere, will feel the same (miniscule) centripetal effects.

I'm afraid you read wrong. The centripetal force on a mass m is given by the formula:

F = m x v^2 /r (mv squared over r)

where v is the surface velocity and r is the radius of rotation.

But w = v / r where w is the angular velocity and so the formula can be rewritten as:

F = m x w^2 x r

This form is more convenient when you know the number of rotations per day, which is an angular velocity.

From this, you should be able to see that, for constant w, the force is proportional to the radius.

 

[geraint]

any object on a sphere that rotates once per day, no matter how big the sphere, will feel the same (miniscule) centripetal effects.

I'm afraid you read wrong. The centripetal force on a mass m is given by the formula:

F = m x v^2 /r (mv squared over r)

where v is the surface velocity and r is the radius of rotation.

But w = v / r where w is the angular velocity and so the formula can be rewritten as:



F = m x w^2 x r

This form is more convenient when you know the number of rotations per day, which is an angular velocity.

From this, you should be able to see that, for constant w, the force is proportional to the radius.

in the original equation... you introduced w... then gave it a value... made it more convenient then made it a constant.....
is there a constant in your equation....if so... what does it stand for...

 

[geraint]

I followed your posts during the (rare) thread that I started until your trolling caused it to get locked. I have no wish to engage further with your posts.
You're now back on ignore.

trolling.....

and now back on ignore.... when was i taken off.... how sad...

 

[penfold46]

wellies. Just a guess though.

 

[lifesagasman]

Baaa-aa-aaaa-r

 

[geraint]

Baaa-aa-aaaa-r

boys will be boys... so what is your excuse.....

 

[geraint]

wellies. Just a guess though.

jesus... at least try to make it original.....

 

[geraint]

I followed your posts during the (rare) thread that I started until your trolling caused it to get locked. I have no wish to engage further with your posts.
You're now back on ignore.

so guess the band then,,,,,,