I would be very grateful for any advice on the following:
I have a large wood turning lathe with mechanical variable speed drive which (the VSD) became u/s, one sliding pulley ran directly on the motor shaft and the shaft worn down after 20 years! The 0.75kw 1 phase motor, with a special shaft, is not easily replaced so I decided to go for an inverter and 3 phase motor driving through fixed ratio pulleys.
I decided my new 3 ph motor should be a bit more powerful to compensate for the lower torque available at low motor rpm and no gearing so bought one with 1.1kw and a 1.5kw inverter to suit. The latter is 1 ph in and 3 out which I intended to supply from a 13amp socket in the workshop.
On receipt of the inverter I noted that the rating plate says max supply current is 17.4 amps. Presumably to allow for losses in the inverter and surges at start up etc.
I am hoping this will still be ok plugged into my 13 amp socket on the basis that my smaller motor will not draw the full current: 17.4A/1500w * 1100w=12.76A drawn and within the rating of the 13A socket.
1) Have I got this wrong and 2) Any tips for setting up/running the inverter. I think it is probably not wise for example to program in extra torque especially as I have already upsized the motor relative to the original
Thanks for any comments
Graham
I have a large wood turning lathe with mechanical variable speed drive which (the VSD) became u/s, one sliding pulley ran directly on the motor shaft and the shaft worn down after 20 years! The 0.75kw 1 phase motor, with a special shaft, is not easily replaced so I decided to go for an inverter and 3 phase motor driving through fixed ratio pulleys.
I decided my new 3 ph motor should be a bit more powerful to compensate for the lower torque available at low motor rpm and no gearing so bought one with 1.1kw and a 1.5kw inverter to suit. The latter is 1 ph in and 3 out which I intended to supply from a 13amp socket in the workshop.
On receipt of the inverter I noted that the rating plate says max supply current is 17.4 amps. Presumably to allow for losses in the inverter and surges at start up etc.
I am hoping this will still be ok plugged into my 13 amp socket on the basis that my smaller motor will not draw the full current: 17.4A/1500w * 1100w=12.76A drawn and within the rating of the 13A socket.
1) Have I got this wrong and 2) Any tips for setting up/running the inverter. I think it is probably not wise for example to program in extra torque especially as I have already upsized the motor relative to the original
Thanks for any comments
Graham