You certainly aren't a pilot or engineer and, if you say differently, either ...
1. You're a fake
or
2. You SERIOUSLY need re-training
Based on your misunderstanding of this problem, that claim scares me.kevnurse said:I am a flight engineer, with nearly 8,000 hrs in my log book.
No (sigh), it means that the wheels rotate, and that they will rotate at twice the speed that they would if the belt (or ground) were static.However, unfortunately, the question places a condition that the speed of the wheels (it doesn't matter what speed it is) is exactly matched by the belt in the opposite direction. This means that the wheels cannot make any progress along the surface of the belt.
It must, and it does, unless you're a fan of the exploding wheels theory.Therefore, the aircraft cannot move relative to the belt, but the thrust theory says it must.
and the belt would move at that same speed because the question says it must. Its a condition of the question. That condition makes the whole question impossible, as a concept. I'm not answering the question. I'm discussing the validity of the question. Your answer only works if the wheels rotate faster than the belt's speed, but the question does not allow you to do that. Its a flawed question.No (sigh), it means that the wheels rotate, and that they will rotate at twice the speed that they would if the belt (or ground) were static.
No - it makes one interpretation of the question lead to a different answer.kevnurse said:That condition makes the whole question impossible, as a concept.
We've already been there and done all that. In spades.I'm not answering the question. I'm discussing the validity of the question.
Since I've given two answers (one for each of two interpretations of the question), which one are you referring to?Your answer only works if the wheels rotate faster than the belt's speed
FFS.Its a flawed question.
Okay, so let's clear one thing up for the benefit of those here who don't know what flight engineers actually do ... You're a dial watching supernumery trolley dolly with the Royal Air Force. We can, therefore, remove the word Engineer from your list of qualifications.I am a flight engineer, with nearly 8,000 hrs in my log book.
Not exactly ... The aircraft engines will accelerate until the point at which the thrust they produce overcomes the mass of the aircraft at which point it will begin to move and will continue to accelerate whilst thrust is in excess of aerodynamic drag and mass. Once takeoff velocity is reached the aircraft will lift off.Of course, thrust is at the heart of the question. Whatever the amount of thrust, the aircraft will accelerate to the point that drag equals thrust and constant speed is then achieved
YES This is the only thing you've posted which is 100% accurate and, if you can see this, I'm not sure how you then go on to post this ...The wheels will free-wheel and they do not enter the discussion in aerodynamics.
This is where you really lose focus. It is totally irrelevant how the aircraft moves relative to the belt it is how the aircraft moves relative to the air that is the key factor i.e. how it moves relative to the ground either side of the belt and, as you have already said (quite correctly) the wheels freewheel and play no part in the take-off process other than the fact that they will be spinning a lot faster than normal ... And they stop the aircraft falling flat on its belly of course (for the pedants )However, unfortunately, the question places a condition that the speed of the wheels (it doesn't matter what speed it is) is exactly matched by the belt in the opposite direction. This means that the wheels cannot make any progress along the surface of the belt. Therefore, the aircraft cannot move relative to the belt, but the thrust theory says it must. I say again, the question is based on false conditions.
The aircraft engines will accelerate until the point at which the thrust they produce overcomes the mass of the aircraft at which point it will begin to move
I am an ex plumbing engineer, with 1 O level (english language) and I concluded this at about page 2 of the LAST debate . How about posting a Q. about a Seaplane on an endless poolI am a flight engineer, with nearly 8,000 hrs in my log book.
I, like many others on here, am an engineer with, as it happens in this case, a degree in Aeronautical engineering and over 12 years experience in aircraft maintenance in my first career. I have also been a pilot since 1983 with over 5000 hours in my log book as pilot in command.
... The aircraft engines will accelerate until the point at which the thrust they produce overcomes the mass of the aircraft at which point it will begin to move and will continue to accelerate whilst thrust is in excess of aerodynamic drag and mass. Once takeoff velocity is reached the aircraft will lift off.
YES This is the only thing you've posted which is 100% accurate and, if you can see this, I'm not sure how you then go on to post this ...The wheels will free-wheel and they do not enter the discussion in aerodynamics.
[ It is totally irrelevant how the aircraft moves relative to the belt it is how the aircraft moves relative to the air that is the key factor i.e. how it moves relative to the ground either side of the belt and, as you have already said (quite correctly) the wheels freewheel and play no part in the take-off process other than the fact that they will be spinning a lot faster than normal ... And they stop the aircraft falling flat on its belly of course (for the pedants )
I do hope you manage to grasp this now, if not, why don't you go and ask one of your pilot chums or, better still, a qualified groundcrew engineer to educate you ... It'll give them a laugh if nothing else.
MW
Now we've established our relative backgrounds ... Back to the discussion, rather than focusing on personal attacks ... Though I'm not excluding the need for further attacks if you keep posting stupid comments.
MW
However, unfortunately, the question places a condition that the speed of the wheels (it doesn't matter what speed it is) is exactly matched by the belt in the opposite direction. This means that the wheels cannot make any progress along the surface of the belt. Therefore, the aircraft cannot move relative to the belt, but the thrust theory says it must. I say again, the question is based on false conditions.