There are 4 of those things my 2 pictures are of each side of the lamp showing 4
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Ah, right - I should have noticed that!There are 4 of those things my 2 pictures are of each side of the lamp showing 4
Indeed so. It's hard to be sure from the photos, but there are probably around 40 LEDs.the components label 9R10 are 9.1 ohm resistors which when in series with 3 LEDs ( volt drop of 9 volts ) would have 3 volts across them ( 12 volt supply ) giving a current of 330 mA ... But there are more LEDs / 3 than ther eare resistors ...
Indeed. Assuming that we're still talking about a 2.5W 12V lamp, that equates to a total current of about 208mA. Assuming 4 series/parallel sub-circuits, each with a 9.1Ω resistor (hence each carrying about 52mA), that could be achieved by, for example, each sub-circuit consisting of 3 sets of 3-LEDs-in-series in parallel (hence ~17mA through each string of LEDs, if current were shared equally) - making a total of 36 LEDs, with ~17mA through each string of LEDs (if current were shared equally), and therefore about 36 x 3 x 17 = 1836 mW, the other 664 mW being 'wasted' in the resistors.Maybe there are two or more strings of 3 series connected LEDs fed by one resistor ( 166 mA or 110 mA per string of three LEDs ) and relies on the LEDs being similar to obtain ressonable current sharing.
More strictly "... can only be varied with average current passing through an LED". LED dimmers will often 'chop' the output so that the current (whether determined by a true 'constant-current' source, or a simple voltage-dependent resistor dropper) does not flow for 100% of the time ('pulse width modulation'). In that way, the average current through the LED (hence brightness of LED) can be varied, even though the current, when flowing (for only some of the time) is constant.So in other words the intensity of an LED can only be varied with current passing through an LED.
LED's do vary in the voltage across them in respect of the current flowing
OK, in that case I assume that each 9.1Ω resistor must serve four parallel strings of three LEDs in series, with ~13mA going through each string of 3 LEDs. Hence (assuming 3V per LED) ~ 48 x 3 x 13 = 1872 mW into the LEDs, and ~628 mW 'wasted' in the resistors.There are 48 leds
Totally agree John. Yes intensity of LEDs and many other things in electrics can be varied by pulse width modulation, meaning how long they are allowed to remain on and then off for a period in time so on off cycling can be used to control intensity, speed of electric motors, heat of electrical elements. etc etc.More strictly "... can only be varied with average current passing through an LED". LED dimmers will often 'chop' the output so that the current (whether determined by a true 'constant-current' source, or a simple voltage-dependent resistor dropper) does not flow for 100% of the time ('pulse width modulation'). In that way, the average current through the LED (hence brightness of LED) can be varied, even though the current, when flowing (for only some of the time) is constant.So in other words the intensity of an LED can only be varied with current passing through an LED.
Kind Regards, John
OK, in that case I assume that each 9.1Ω resistor must serve four parallel strings of three LEDs in series, with ~13mA going through each string of 3 LEDs. Hence (assuming 3V per LED) ~ 48 x 3 x 13 = 1872 mW into the LEDs, and ~628 mW 'wasted' in the resistors.There are 48 leds
Kind Regards, John
That's obviously part of it. If my guesstimates are roughly correct, then only 1.872W is actually 'getting to' the LEDs (the rest of the 2.5W being 'wasted' in the resistors), so that would be about 80 lm per W in terms of the LEDs themselves. Using resistors as the current-controlling method inevitably results in such wastage/inefficiency, reflected in an appreciable deterioration in the overall lm per W (that being supplied Watts) figure. Other means of current control can theoretically be much more efficient.So is that why it is 2.5w but only giving 15olm which is 60 lm per W... Hence (assuming 3V per LED) ~ 48 x 3 x 13 = 1872 mW into the LEDs, and ~628 mW 'wasted' in the resistors.
Is the problem with these tiny tiny units that a better means of control would be too big to fitThat's obviously part of it. If my guesstimates are roughly correct, then only 1.872W is actually 'getting to' the LEDs (the rest of the 2.5W being 'wasted' in the resistors), so that would be about 80 lm per W in terms of the LEDs themselves. Using resistors as the current-controlling method inevitably results in such wastage/inefficiency, reflected in an appreciable deterioration in the overall lm per W (that being supplied Watts) figure. Other means of current control can theoretically be much more efficient.So is that why it is 2.5w but only giving 15olm which is 60 lm per W... Hence (assuming 3V per LED) ~ 48 x 3 x 13 = 1872 mW into the LEDs, and ~628 mW 'wasted' in the resistors.
Kind Regards, John
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