[DA]But what if the fault is at the end of a couple of m of 0.5mm² flex and the total fault loop impedance means that the fault current is < 5In?[/DA]
Whatever the [DA]...[/DA] was designed to achieve, the system clearly hasn't recognised it
Yes, as I said, everything is inevitably dependent on the fault current, and if it's going to be <5I
n, then one has to rework the calculations accordingly. However, a couple of metres of 0.5mm² flex (about 176mΩ
will often not make the difference between a fault current <5I
n and a fault current >5I
n. If, for example, the fault current would have been 240A without the flex in the fault circuit, with that flex it would fall to about 203A - but I agree it could if the FLI would not have been much above 5I
n (i.e. 200A for a 40A MCB) without the flex. Also note that my calculations were addressing your question in relation to
2.5mm² cable, for which a 40A Type B MCB provides far more protection than necessary with a fault current ≥200A - but that, with that fault current, the MCB wouldn't be quite adequate for 0.5mm² conductors (only for ≥0.55mm²).
There is, of course, also a caveat I should have added. In the case of a TT installation, the fault protection calculations I presented obviously only apply in the case of L-N faults. With an L-E fault on most TT installations, the fault current will not be high enough to operate even a 6A MCB (ever), let alone one of higher rating – so L-E fault protection in that situation has to be reliant upon an RCD. However, given the characteristics of RCDs, I would have thought that protection will probably always be at least as adequate as corresponding protection from an MCB would have been.
Kind Regards, John.