Hello Roger
The reason you have the question is that you're confusing yourself with your own terminology. Things should become clearer to you if you consider the question "
At what current will the RCD detect an imbalance and trip?".
In case that didn't help, I'll continue...
gw3xjc said:
Ok Softus I will try an explain my question in a different way to you.
The clue for you was the LARGE imbalance due to a SHORT circuit rather than a LEAKAGE :
The reason that this wasn't a clue "for me" is because they are the same thing "to me", but I can see that they're not to you.
If the live was leaking down to earth via a couple of k I would expect the rcd to blow, right?
Assuming that by "k" you mean 1,000 Ohms, then, in your example, the current would, in simplistic form, be (230 Volts / 2000 Ohms ) = 115 milliAmps.
Based on the above calculation, a 30mA RCD (or even 100mA) would be expected to trip, if the current were sustained for long enough. I don't know how you arrived at that conclusion though. Did you guess?
It has 230 volts on with respect to earth. Now I know if I SHORT CIRCUIT neutral to earth the rcd will trip.
If by "SHORT" you mean a sufficiently low resistance for the RCD to trip, then I'd have to agree.
What I Don't know is if the neutral was LEAKING to earth via the same scenario as above, a couple of k would it still trip as the neutral only has a very small amount of voltage above the earth potential.
In your example, if there were no leakages from other circuits supplied by the same RCD, then it wouldn't trip. But it isn't because you've used the word "LEAKING", it's because the resistance, at 2K Ohms, is sufficiently high.
Does that mean that it's not your time of the month?